Given the equation:
\qquad y = A_DISPx^2 + -2 * A * Hx + A * H * H + K
Find the parabola's vertex.
\large{\left(\right.}H,\text{ }K\large{\left.\right)}
(-1, 2) When the equation is rewritten in vertex form like this, the vertex is the point (h, k):
\qquad formatGroup( GROUP1, [ 0 ] )
We can rewrite the equation in vertex form by completing the square. First, move the constant term to the left side of the equation:
\qquad formatGroup( COMP_SQR1, [ 0, 1 ] )
Next, we can factor out a A from the right side:
\qquad formatGroup( COMP_SQR2, [ 0 ] )
We can complete the square by taking half of the coefficient of our x term, squaring it, and adding it to both sides of the equation.
The coefficient of our x term is -2 * H, so half of it would be -H,
and squaring that gives us H * H. Because we're adding the H * H
inside the parentheses on the right where it's being multiplied by A, we need to add A * H * H
to the left side to make sure we're adding the same thing to both sides.
\qquad formatGroup( COMP_SQR3, [ 0, 1, 2 ] )
Now we can rewrite the expression in parentheses as a squared term:
\qquad formatGroup( COMP_SQR4, [ 0 ] )
Move the constant term to the right side of the equation. Now the equation is in vertex form:
\qquad formatGroup( COMP_SQR5, [ 0 ] )
Now that the equation is written in vertex form, the vertex is the point (h, k):
\qquad formatGroup( GROUP1, [ 0 ] )
The vertex is (H, K). Be sure to pay attention to the signs when interpreting an equation in vertex form.